2 条题解

  • 1
    @ 2024-7-25 12:57:53

    参考答案:

    #include<iostream>
    
    using namespace std;
    
    int main() 
    {
        int a, b, c;
    
        cin >> a >> b >> c;
    
        double x = (a + b + c) / 3.0;
        if (x >= 60) cout << "No" << endl;
        else cout << "Yes" << endl;
    
        return 0;
    }
    
    • 0
      @ 2025-10-17 14:10:46

      Python:

      a, b, c = map(int, input().split())
      sav_score = (a + b + c)/3
      if sav_score >=60:
          print('No')
      else:
          print('Yes')
      
      • 1

      信息

      ID
      41
      时间
      1000ms
      内存
      256MiB
      难度
      9
      标签
      递交数
      8
      已通过
      8
      上传者