参考答案：

#include<iostream>
#include<cmath>
using namespace std;
const int N = 1010;
int a[N][N];
int n;
int main()
{
    int x = 0, y = 0;
    cin >> n;

    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j <= n; j++) 
        {
            cin >> a[i][j];
            if (a[i][j] == 1) 
            {
                x = i, y = j;
                break;
            }
        }
    }
    cout << abs(x - 3) + abs(y - 3) << endl;


    return 0;
}