1 条题解
-
0
参考答案:
#include<iostream> #include<algorithm> #include<string> using namespace std; int main() { string s1, s2; cin >> s1 >> s2; if (s2[0] == 'e' && s1[0] == 't' || s2[0] == 't' && s1[0] == 'c' || s2[0] == 'c' && s1[0] == 'm' || s2[0] == 'm' && s1[0] == 'e') cout << "tiangou txdy"; else cout << "tiangou yiwusuoyou"; return 0; }
- 1
信息
- ID
- 5419
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- 递交数
- 4
- 已通过
- 2
- 上传者