1 条题解
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1
/** * author: 小飞侠 * created: 2024.10.22 20:33:20 */ #include <bits/stdc++.h> using namespace std; #define ls u << 1 #define rs u << 1 | 1 #define LL long long #define int long long #define PII pair <int, int> #define fi first #define se second #define pub push_back #define pob pop_back #define puf push_front #define pof pop_front #define lb lower_bound #define ub upper_bound #define i128 __int128 #define pcnt(x) __builtin_popcount(x) #define mem(a,goal) memset(a, (goal), sizeof(a)) #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --)) #define aLL(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() const int INF = 998244353; const int P = 1e9 + 7; const int N = 2e5 + 5; int a[N]; int cnt[200][N]; int ans; int n; void solve() { cin >> n; string s; cin >> s; for(int i = 0; i < n; ++ i) cnt[s[i] - 'a'][i] ++; for(int i = 0; i < 26; ++ i) { for(int j = 1; j < n; ++ j) { cnt[i][j] += cnt[i][j - 1]; } } for(int i = 0; i < n; ++ i) { int t = s[i] - 'a'; for(int j = 0; j < 26; ++ j) { if(j == t) continue; ans += (cnt[j][n - 1] - cnt[j][i]) * ((cnt[j][n - 1] - cnt[j][i]) - 1)/ 2; } } cout << ans << '\n'; } signed main() { solve(); return 0; }
- 1
信息
- ID
- 5474
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- 递交数
- 8
- 已通过
- 2
- 上传者