1 条题解

  • 1
    @ 2024-7-25 13:18:55

    参考答案:

    #include<iostream>
    
    using namespace std;
    
    const int N = 200010;
    int a[N], tmp[N];
    
    void merge_sort(int a[], int l, int r)
    {
        if (l >= r) return;
    
        int mid = l + r >> 1;
        merge_sort(a, l, mid);
        merge_sort(a, mid + 1, r);
        int k = 0; int i = l, j = mid + 1;
    
        while (i <= mid && j <= r)
        {
            if (a[i] < a[j]) tmp[k++] = a[i++];
            else tmp[k++] = a[j++];
        }
    
        while (i <= mid) tmp[k++] = a[i++];
        while (j <= r) tmp[k++] = a[j++];
    
        for (int i = l, j = 0; i <= r; ++i, ++j) a[i] = tmp[j];
    }
    int main()
    {
        int n;
        cin >> n;
    
        for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
    
        merge_sort(a, 0, n - 1);
    
        for (int i = 0; i < n; ++i) printf("%d ", a[i]);
    
        return 0;
    }
    
    • 1

    信息

    ID
    78
    时间
    1000ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    6
    已通过
    2
    上传者