1 条题解

  • 0
    @ 2024-7-25 13:23:03

    参考答案:

    #include<iostream>
    
    using namespace std;
    
    const int N = 1010;
    int b[N][N], s[N][N];
    int n, m, q;
    
    void insert(int x1, int y1, int x2, int y2, int c)
    {
        b[x1][y1] += c;
        b[x1][y2 + 1] -= c;
        b[x2 + 1][y1] -= c;
        b[x2 + 1][y2 + 1] += c;
    }
    
    int main()
    {
        cin >> n >> m >> q;
    
        for (int i = 1; i <= n; ++i)
            for (int j = 1; j <= m; ++j)
            {
                scanf("%d", &s[i][j]);
                insert(i, j, i, j, s[i][j]);
            }
    
        while (q--)
        {
            int x1, y1, x2, y2, c;
            scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &c);
            insert(x1, y1, x2, y2, c);
        }
    
        for (int i = 1; i <= n; ++i)
            for (int j = 1; j <= m; ++j)
                b[i][j] += b[i - 1][j] + b[i][j - 1] - b[i - 1][j - 1];
    
        for (int i = 1; i <= n; ++i)
        {
            for (int j = 1; j <= m; ++j)
                printf("%d ", b[i][j]);
            printf("\n");
        }
    
        return 0;
    }
    
    • 1

    信息

    ID
    62
    时间
    1500ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    7
    已通过
    2
    上传者