1 条题解
-
0
参考答案:
#include<iostream> using namespace std; const int N = 100010; int p[N], cnt[N]; int find(int x) { if (p[x] != x) p[x] = find(p[x]); return p[x]; } int main() { int n, m; cin >> n >> m; for (int i = 1; i <= n; ++i) p[i] = i, cnt[i] = 1; while (m--) { string s; cin >> s; if (s == "C") { int a, b; cin >> a >> b; a = find(a), b = find(b); if (a != b) { p[a] = b; cnt[b] += cnt[a]; } } else if (s == "Q1") { int a, b; cin >> a >> b; if (find(a) == find(b)) cout << "Yes" << endl; else cout << "No" << endl; } else { int a; cin >> a; cout << cnt[find(a)] << endl; } } return 0; }
- 1
信息
- ID
- 85
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- 递交数
- 13
- 已通过
- 3
- 上传者