1 条题解
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1
#include <bits/stdc++.h> using namespace std; #define ls u << 1 #define rs u << 1 | 1 #define LL long long #define int long long #define PII pair <int, int> #define fi first #define se second #define pub push_back #define pob pop_back #define puf push_front #define pof pop_front #define lb lower_bound #define ub upper_bound #define i128 __int128 #define pcnt(x) __builtin_popcount(x) #define mem(a,goal) memset(a, (goal), sizeof(a)) #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --)) #define aLL(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() const int INF = 998244353; const int mod = 1e9 + 7; const int N = 1010; int g[N][N], dis[N][N]; int dx[] = {0, 1, 0, -1}; int dy[] = {1, 0, -1, 0}; int n, m; void bfs(int a, int b) { memset(dis, -1, sizeof(dis)); dis[a][b] = 0; queue<PII> q; q.push({a, b}); while(q.size()) { PII t = q.front(); q.pop(); for(int i = 0; i < 4; ++ i) { int x = t.first + dx[i], y = t.second + dy[i]; if(x >= 0 && x < n && y >= 0 && y < m && dis[x][y] == -1 && g[x][y] == 0) { dis[x][y] = dis[t.first][t.second] + 1; q.push({x, y}); } } } cout << dis[n - 1][m - 1] << '\n'; } void solve() { scanf("%lld%lld", &n, &m); for(int i = 0; i < n; ++ i) for(int j = 0; j < m; ++ j) scanf("%lld", &g[i][j]); bfs(0, 0); } signed main() { int t = 1; while (t --) solve(); return 0; }
- 1
信息
- ID
- 90
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- 递交数
- 10
- 已通过
- 4
- 上传者