1 条题解
-
1
参考答案:
#include<iostream> #include<cstring> using namespace std; const int N = 510; int g[N][N]; int dis[N]; int n, m; int st[N]; int dijkstra() { memset(dis, 0x3f, sizeof dis); dis[1] = 0; for (int i = 1; i < n; ++i) { int t = -1; for (int j = 1; j <= n; ++j) { if (!st[j] && (t == -1 || dis[j] < dis[t])) t = j; } st[t] = 1; for (int j = 1; j <= n; ++j) { dis[j] = min(dis[j], dis[t] + g[t][j]); } } return dis[n]; } int main() { cin >> n >> m; memset(g, 0x3f, sizeof g); for (int i = 1; i <= m; ++i) { int x, y, z; cin >> x >> y >> z; g[x][y] = min(g[x][y], z); } if (dijkstra() == 0x3f3f3f3f) cout << "-1"; else cout << dis[n]; return 0; }
- 1
信息
- ID
- 94
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 5
- 已通过
- 2
- 上传者