1 条题解
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1
参考答案:
#include<iostream> #include<algorithm> using namespace std; const int N = 100010, M = 2 * N, INF = 0x3f3f3f3f; int p[N]; int n, m; struct Edge { int a, b, c; bool operator<(const Edge& W) const { return c < W.c; } }edge[M]; int find(int x) { if (p[x] != x) p[x] = find(p[x]); return p[x]; } int kruskal() { sort(edge + 1, edge + m + 1); int res = 0, t = 0; for (int i = 1; i <= m; ++i) { int a = edge[i].a, b = edge[i].b, c = edge[i].c; a = find(a), b = find(b); if (a != b) { p[a] = b; res += c; t++; } } if (t < n - 1) return INF; return res; } int main() { cin >> n >> m; for (int i = 1; i <= n; ++i) p[i] = i; for (int i = 1; i <= m; ++i) { cin >> edge[i].a >> edge[i].b >> edge[i].c; } int t = kruskal(); if (t == INF) cout << "Not exist" << endl; else cout << t << endl; return 0; }
- 1
信息
- ID
- 103
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 2
- 已通过
- 2
- 上传者