1 条题解
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1
#include <bits/stdc++.h> using namespace std; #define ls u << 1 #define rs u << 1 | 1 #define LL long long #define int long long #define PII pair <int, int> #define fi first #define se second #define pub push_back #define pob pop_back #define puf push_front #define pof pop_front #define lb lower_bound #define ub upper_bound #define i128 __int128 #define pcnt(x) __builtin_popcount(x) #define mem(a,goal) memset(a, (goal), sizeof(a)) #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --)) #define aLL(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() const int INF = 998244353; const int mod = 1e9 + 7; const int N = 100010; int st[N], primes[N]; int cnt; void get() { for(int i = 2; i < 40001; ++ i) { if(!st[i]) primes[cnt ++] = i; for(int j = 0; i * primes[j] < 40001; ++ j) { st[i * primes[j]] = 1; if(i % primes[j] == 0) break; } } } void solve() { get();//2262 int n, m, res = 0; cin >> n >> m; vector<int> a(n, 0), b(m, 0); for(int i = 0; i < n; ++ i) cin >> a[i]; for(int i = 0; i < m; ++ i) cin >> b[i]; sort(a.begin(), a.end()); sort(b.begin(), b.end()); for(int i = 0; i < cnt; ++ i) { int t = primes[i]; if(t > n + m) break; int l = 0, r = m - 1; while(l < n && r >= 0) { if(a[l] + b[r] > t) { -- r; continue; } if(a[l] + b[r] < t) { ++ l; continue; } if(a[l] + b[r] == t) { ++ res; break; } } } cout << res << '\n'; } signed main() { int t = 1; while (t --) solve(); return 0; }
- 1
信息
- ID
- 5563
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者