1 条题解
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1
/** * author: 小飞侠 * created: 2024.11.11 23:12:26 */ #include <bits/stdc++.h> #define ls u << 1 #define rs u << 1 | 1 #define LL long long #define int long long #define PII pair <int, int> #define fi first #define se second #define pub push_back #define pob pop_back #define puf push_front #define pof pop_front #define lb lower_bound #define ub upper_bound #define i128 __int128 #define pcnt(x) __builtin_popcount(x) #define mem(a,goal) memset(a, (goal), sizeof(a)) #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --)) #define aLL(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() const int INF = 998244353; const int P = 1e9 + 7; const int N = 2e5 + 5; void solve() { int n; std:: cin >> n; std:: vector<int> a(n + 1), s(n + 1); for(int i = 1; i <= n; ++ i) { std:: cin >> a[i]; s[i] = s[i - 1] + a[i]; } int ans = 0; int maxx = -1e9 - 10; for(int i = 1; i <= n; ++ i) { maxx = std:: max(maxx, a[i]); if(s[i] - maxx == maxx) ans ++; } std :: cout << ans << '\n'; } signed main() { int t; std:: cin >> t; while(t --) solve(); return 0; }
- 1
信息
- ID
- 5473
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- (无)
- 递交数
- 10
- 已通过
- 3
- 上传者