参考答案：

#include<iostream>
using namespace std;
const int N = 110;
int a[N][N];
int main()
{
    int t = 0;
    for (int i = 1; i <= 9; ++i)
        for (int j = 1; j <= 9; ++j)
            cin >> a[i][j];
    for (int i = 1; i <= 9; ++i)//每行
    {
        int sum = 0;
        for (int j = 1; j <= 9; ++j) sum += a[i][j];
        if (sum != 45) t = 1;
    }
    for (int i = 1; i <= 9; ++i)//每列
    {
        int sum1 = 0;
        for (int j = 1; j <= 9; ++j) sum1 += a[j][i];
        if (sum1 != 45) t = 1;
    }
    for (int i = 1; i <= 9; i += 3)
    {
        for (int j = 1; j <= 9; j += 3)
        {
            int sum2 = 0;
            for (int m = i; m <= i + 2; ++m)
            {
                for (int n = j; n <= j + 2; ++n)
                {
                    sum2 += a[m][n];
                }
            }
            if (sum2 != 45) t = 1;
        }
    }
    if (t == 1) cout << "NO" << endl;
    else cout << "YES" << endl;
  
    return 0;
}